एक समकोण त्रिभुज का परिमाप क्या है जिसकी भुजाएँ 90 बनाते हुए 20 √ 3 सेमी और 15 √ 3 सेमी हैं? - ek samakon tribhuj ka parimaap kya hai jisakee bhujaen 90 banaate hue 20 √ 3 semee aur 15 √ 3 semee hain?

एक समकोण त्रिभुज का परिमाप क्या है जिसकी भुजाएँ (90° बनाते हुए) 20√3 सेमी और 15√3 सेमी हैं?

1. 65√3 सेमी 
2. 60√3 सेमी 
3. 50√3 सेमी 
4. 55√3 सेमी 

Answer (Detailed Solution Below)

Option 2 : 60√3 सेमी 

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दिया गया है:

समकोण त्रिभुज की भुजाएँ = 20√ 3 सेमी और 15√ 3 सेमी

प्रयुक्त सूत्र:

कर्ण2 = लंब2 + आधार2

त्रिभुज का परिमाप = a + b + c

गणना​:

एक समकोण त्रिभुज की ऊंचाई और आधार क्रमशः 20√ 3 सेमी और 15√ 3 सेमी है। 

समकोण त्रिभुज के लिए,

कर्ण2 = लंब2 + आधार2

⇒ कर्ण2 = (20√3)2 + (15√3)2

⇒ कर्ण2 = (1200) + (675)

⇒ कर्ण2 = 1875

⇒ कर्ण= 25√3

त्रिभुज का परिमाप = (20√3 + 15√3 + 25√3) सेमी 

⇒ 60√3 सेमी 

∴ त्रिभुज का परिमाप 60√3 सेमी है। 

Last updated on Oct 18, 2022

SSC CHSL Preference Selection Form has been released for the 2020 cycle on 27th October 2022. SSC CHSL Error Percentage for the candidates who have appeared in the Skill Test (DEST/Typing Test) 2020 has been uploaded on the official website. Candidates can log in to their profiles and check individual marks between 26th November 2022 to 16th November 2022. The SSC is going to release the SSC CHSL notification on 5th November 2022. Candidates who have completed Higher Secondary (10+2) can appear for this exam for recruitment to various posts like Postal Assistant, Lower Divisional Clerks, Court Clerk, Sorting Assistants, Data Entry Operators, etc. The SSC Selection Process consists of Computer Based Exam, Descriptive Test and Typing/Skill Test. Recently, the board has released the SSC CHSL Skill Test Result for the 2020 cycle. The candidates who are qualified are eligible to attend the document verification. 

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